Id_ad=1929170&action There's a bunch of text which may or may not include integers (that I don't want) and then there's a line that always contains id_ad=1889170&action and then followed by a bunch of garbage I don't care about, again it may or may not include one or more integers. I spent (wasted) a couple hours reading tutorials and I feel no closer to an answer :( There's a bunch of text which may or may not include integers (that I don't want) and then there's a line that always contains
#Extract .nki files using cdxtract how to
I want to process the body of text and extract an integer from a specific position in the text, but I'm not sure how to describe that 'particular position'. Run the above script as, python3 script.py /path/to/the/file Print(f) # Print each element from the list L in a separate new line. L.append(i) # Append the extracted digits to the already declared empty list L.įor f in L: # Iterate through all the elements in the list L Example stolen from Jacob's post.įor j in src: # iterate through all the linesįor i in re.findall(r'id_ad=(\d+)&action', j): # extracts the digits which was present in-between `id_ad=` and `&action` strings. *(?=&action): (positive lookahead) matches 0 or more occurrences of numbers that is followed by pattern( &action), without making the pattern( &action) part of the match.Īnother python answer through re module. (?=pattern): Positive Lookahead: The positive lookahead construct is a pair of parentheses, with the opening parenthesis followed by a question mark and an equals sign. (?<=id_ad=)* (positive lookbehind) matches the 0 or more occurrences of numbers which followed after id_ad= in filename. A pair of parentheses, with the opening parenthesis followed by a question mark, "less than" symbol, and an equals sign. Returns any number with 0 or more occurrences( *) between two START word( id_ad=) and END word( &action) in filename. Interpret PATTERN as a Perl compatible regular expression (PCRE) With each such part on a separate output line.
Print only the matched (non-empty) parts of a matching line, See for more about sed command With grep: Explanation: grep -Po '(?<=id_ad=)*(?=&action)' filename
*: Any number with 0 or more occurrences. And with \1 we print the its group index(we have one capture group)īetter sed command for above solution can be like this: sed 's/^id_ad=\(*\)&action/\1/' filename \( is start of a capturing group and end with \). *) between two START word( id_ad=) and END word( &action) in filename. With sed: sed 's/id_ad=\(.*\)&action/\1/' filenameĪbove command returns any strings(. If there is only one occurrence in the text file, the script can be much shorter: #!/usr/bin/env python3 Paste the script into an empty file, save it as extract.py run it by the command: python3 There's a bunch of text which may or may not include integers (that I don't want) and then there's a line that always contains id_ad=1929990&action" There's a bunch of text which may or may not include integers (that I don't want) and then there's a line that always contains id_ad=1889170&action and then followed by a bunch of garbage I don't care about, again it may or may not include one or more integers. Id_ad=1889170&action and then followed by a bunch of garbage I don't care about, again it may or may not include one or more integers. There's a bunch of text which may or may not include integers (that I don't want) and then there's a line that always contains I spent (wasted) a couple hours reading tutorials and I feel no closer to an answer :(
" I want to process the body of text and extract an integer from a specific position in the text, but I'm not sure how to describe that 'particular position'. Then it prints all that is between those "markers". The script first lists all occurrences (indexes) of the (start) string "id_ad=", in combination with (end) string "&action". find("&action")+i) for i in range(len(text)) if text = "id_ad="] Not so much a one liner (although the command to run it is a one liner :) ), but here is a python option: #!/usr/bin/env python3
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